Question 267716
I have to solve using the principle of zero product 
b(b+16)(b+3)=0 I know I have to set each to zero...but unclear on how to set it up...please help


We know a product of numbers equals 0 if and only if at least one of numbers is 0.

In this case the product is zero if b = 0 and/or (b+16) = 0 and/or (b+3) = 0.

So the solutions for b in this equation are:

1.) b = 0

b+16 = 0 so
2.) b = -16 

b+3 = 0 so
3.) b = -3