Question 267648
Think of f(5)=-5 and f(-25) = -25 as points (5,-5) and (-25,-25).  Use these 2 points to write the equation of the line that passes through them (because the problem said that this was a linear function).  First find the slope
(-25--5)/(-25-5) = -20/30 which is -2/3.  Using the slope intercept form of the line we would have y=-2/3x + b the plug in one of the points to find b.  I will use (5,-5)
-5=-2/3(5)+b
-5 = -10/3+b
-5+10/3 = b
-15/3 +10/3 = b
-5/3 = b
Our function is y=-2/3x-5/3
so f(2) = -2/3(2)-5/3
        -4/3-5/3
        =-9/3
        =-3
f(50) = -2/3(50)-5/3
      =-100/3-5/3
      =-105/3
      =-35