Question 33190
{{{y+3=(1/10) (x+2)^2}}} 
STANDARD EQN.OF PARABOLA IS 
(X-H)^2=4A(Y-K)...WHERE
FOCUS IS (H,K+A)
DIRECTRIX IS Y-K+A=0
AXIS IS X-H=0
VERTEX IS (H,K)
HERE WE HAVE 
(X+2)^2=10(Y+3)...SO COMPARING WE GET
H=-2.....K=-3.....4A=10...OR...A=2.5...HENCE 
DIRECTRIX IS GIVEN BY
Y-K+A=0....OR.....
Y-(-3)+2.5=0
Y+3+2.5=0
Y+5.5=0
2Y+11=0