Question 267520
I am trying to help my son with this question:

{{{((6x-3)/(5x^2))/((2x-1)/(10x))}}}
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That is the same as

{{{(6x-3)/(5x^2)}}}{{{"÷"}}}{{{(2x-1)/(10x)}}}

Now invert the second fraction and change the division sign
to multiplication (we use * instead of "×" so we don't confuse
it with the variable x}

{{{(6x-3)/(5x^2)}}}{{{"*"}}}{{{(10x)/(2x-1)}}}

Factor the left numerator:

{{{(3(2x-1))/(5x^2)}}}{{{"*"}}}{{{(10x)/(2x-1)}}}

Indicate the multiplication of the numerators over the
indicated multiplication of the denominators:

{{{(3(2x-1)(10x))/(5x^2(2x-1))}}}

Cancel the {{{(2x-1)}}}'s

{{{(3(cross(2x-1))(10x))/(5x^2(cross(2x-1)))}}}

That leaves:

{{{(3*(10x))/(5x^2)}}}

Cancel the 5 into the 10, getting 2 in the top:

   {{{2}}}
{{{(3*(cross(10)x))/(cross(5)x^2)}}}

That leaves

{{{(6x)/(x^2)}}}

The x in the top cancels the square in the bottom:

{{{(6cross(x))/(x^cross(2))}}}

And the final simplified answer is

{{{6/x}}}

Edwin</pre>


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