Question 267282
A chemist wishes to mix some pure acid with some water to produce 16L of a solution that is 30% acid.
 How much pure acid and how much water should be mixed
:
let x = amt of pure acid
:
x = .30(16)
x = 4.8 liters of pure acid
then
16-4.8 = 11.2 liters of water
:
:
Check: {{{4.8/16}}} = .3 or 30% acid
and: {{{11.2/16}}} = .7 or 70% water