Question 267239
This conic is a hyperbola. The adjusted equation after completing the square is
{{{(x-2)^2 - 4(y+2)^2 = 4 +4+4}}}
or
{{{(x-2)^2/12 - (y+2)^2/3 = 1}}}
The center is (2, -2)
The foci are sqrt(12+3) = sqrt(15)
The coordinates of the foci are
(2 +- sqrt(15), -2)