Question 267319
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Use the quadratic formula.  For any quadratic equation of the form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ax^2\ +\ bx\ +\ c\ =\ 0]


The two roots are given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a}]


For your equation *[tex \LARGE a\ =\ 1], *[tex \LARGE b\ =\ 6], and *[tex \LARGE  c\ =\ 6].  Just substitute the values:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ t = \frac{-(6)\ \pm\ \sqrt{(6)^2\ -\ 4(1)(6)}}{2(1)}]


Just do the arithmetic and simplify.  If you need help simplifying the radical expression, write back.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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