<PRE><B>Question 267027</B>
A B747 aircraft flew 6 hours w/wind speed return trip took 7 hours against wind if the speed of the plane in air is 13 times speed of wind find the wind speed and the speed of the plane in still air solve by substitution or elimination.
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I don&#39;t think there is a unique solution to this problem, as we can see as we proceed.
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Let s = speed of the plane
Let w = speed of the wind
:
Write a distance equation for the statement. dist = time * speed
7(s - w) = 6(s + w)
7s - 7w = 6s + 6w
7s - 6s = 6w + 7w
s = 13w, which is what the problem states
:
Substitute a value for w, find s
A few solutions
w | s
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20|260
25|325
40|520

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