Question 266971
plz solve my question 
Given a normal distribution with u=40 and variance=6 find the value of x that has 
(i) 38% of the area below it 
1st: Find the z-value that has 38% to its left.
invNorm(0.38) = -0.3055
2nd: use x = zs+u to find your answer:
x = -0.3055*6 + 40
x = 38.17
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(ii) 5% of the area above it.
1st: Find the z-value that has 5% above it
invNorm(0.95) = 1.645
Then x = 1.645*6+40
x = 49.87
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Cheers,
Stan H.
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