Question 266931
{{{-3<2-5x<=12}}}
{{{-3<2-5x}}}, {{{2-5x<=12}}} seperate equations
solve seperatly
{{{-3<2-5x}}}
{{{-3-2<2-5x-2}}}
{{{-5/-5<-5x/-5}}}
{{{1>x}}}
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{{{2-5x<=12}}}
{{{2-5x-2<=12-2}}}
{{{-5x/-5<=10/-5}}}
{{{x>=-2}}}
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{{{-2<=x<1}}} is the solution