Question 266797
From above we get the following:
(i) {{{x = 5 + y}}}
(ii) {{{x^2 + 27 = -7y}}}
substitute (i) into (ii) to get
(iii) {{{(5+y)^2 + 27 = -7y}}}
expand to get
(iv) {{{y^2 + 10y + 25 + 27 = -7y}}}
combine like terms and set = 0 to get
(v) {{{y^2 + 17y + 52 = 0}}}
factoring, we get
(vi) {{{(y+13)(y+4) = 0}}}
and solving for y, we get
 y = -13 or y= -4
our two possible answers are:
(-8,-13) and (1,-4)
but we can't use the second.