Question 266767
Let x, x+1, and x+2 be the integers
From above ,we get
{{{x + 2*(x+1) = 122 - 3*(x+2)}}}
distribute to get
{{{x + 2x + 2 = 122 -3x - 6}}}
combine like terms to get
{{{3x + 2 = 116 - 3x}}}
add 3x and subtract 2 to get
{{{6x = 114}}}
divide to get
{{{x = 19}}}
the three numbers are 19, 20, and 21