Question 266681
here is our original equation
(i) {{{ax - 3x + 5 = a + b}}}
step 1 - subtract 5 to get
(ii) {{{ax - 3x = a + b - 5}}}
step 2 - take out the gcf to get
(iii) {{{x(a-3) = a + b - 5}}}
step 3 - divide by a-3 to get
(iv) {{{x = (a + b - 5)/(a-3)}}}
restrictions: a cannot = 3