Question 266658
<pre>
Not sure if I am doing this correctly:
{{{8(y+3)=3(2y+12)}}}
{{{8y+24=6y+36}}}

That is good, you used the distributive principle

{{{cross(2y+24=12)}}}

That is wrong because when you add -24 to both sides you 
no longer have the +24 on the left, but only

{{{2y = 12}}}

Then you divide both sides by 2 and get

{{{y=6}}}

Edwin</pre>