Question 266560
here is the original system:
(i) {{{6m + n = 23}}}
(ii) {{{m - 6n = 10}}}
since we must use substitution, we can solve (i) for n and get
(iii) {{{n = -6m + 23}}}
substitute (iii) into (ii) to get
(iv) {{{m - 6*(-6m + 23) = 10}}}
distribute and simplify to get
(v) {{{m + 36m  - 138 = 10}}}
combine like terms to get
(vi) {{{37m - 138 = 10}}}
add 138 to get
(vii) {{{37m = 148}}}
divide by 37 to get
(viii) {{{m = 4}}}
now,
{{{n = -1}}}
So, we get
(4,-1)