Question 266556
here is the equation:
(i) {{{16(x-a) = 4(2a-x)}}}
step 1 - distribute to get
(ii) {{{16x - 16a = 8a - 4x}}}
step 2 - add 4x and add 16a to get
(iii) {{{20x = 24a}}}
solving for x, we get
 (iv) {{{x = (6/5)a}}}