Question 266488
t^3-8

=> {{{t^3-2^3}}}

it is of the form a^3-b^3

we have (a^3-b^3)=(a-b)(a^2+ab+b^2)

similarly 

  (t^3-2^3)=(t-2)(t^2+2t+4)

so t^3-8 = (t-2)(t^2+2t+4)