Question 33167
FIRST FORM EQUATIONS WITH THE INFORMATIONS GIVEN IN THE QUESTION.
 
let the numbers be X & Y,

 The diff. of the two numbers is 47 and is written as,

  EQ 1.    X - Y = 47
  
  EQ 2.    X = 3 + 5*Y   

Put the value of X (FROM EQ 2) IN  EQ 1 .,
   
 3 + 5Y - Y = 47
      4Y  = 47 -3
       Y = 44/4
         = 11.

PUT Y = 11 IN EQ 1.,
   we get X = 47 + 11
             = 58.

The numbers are 58 and 11.

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