Question 266268
<pre><font size = 4 color = "indigo"><b>
Of the 7 coins there are 6 non-quarters. If she doesn't get
the quarter, then the only way she could fail to get less
than 25 cents would be to get 2 dimes and 1 nickel.  Since 
there are only 2 dimes, to fail she must get them both, and 
since there are 3 nickels she can get 2 dimes and 1 nickel 
exactly 3 ways. So the number of successful ways to get less 
than 25 cents is the number of ways to get any 3 of the the 
6 non-quarters minus the 3 ways to get 2 dimes and a nickel.
That is,

 (6C3 - 3) ways

The number of ways of getting any 3 of the coins is 7C3.

So the desired probability is 

{{{(6C3-3)/(7C3) = (20-3)/35 = 17/35}}}

The correct choice is (A)

Edwin</pre>