Question 266193
when a fair die is rolled once the probability of a particular number to come is 1/6

now the die is rolled 6 times and we need to have no 1 and no 2 among the rolls

so out of any 6 outcomes the required no.s can come 

so the no. of ways of those two outcomes is 6C2 = 15

so the probability of no 1 and no 2 coming in these two outcomes is

  15*(1/6)*(1/6)=15/36=  0.416666 = 0.417 Answer