Question 266193
A fair die is rolled 6 times. What is the probability of having no 1 and no 2 among the rolls?

The probability of getting a 3, 4, 5 or 6 the 1st time is 4 ways out of 6, which is {{{4/6}}} or {{{2/3}}}
multiplied by
the probability of getting a 3, 4, 5 or 6 the 2nd time, or {{{2/3}}}
multiplied by
the probability of getting a 3, 4, 5 or 6 the 3rd time, or {{{2/3}}}
multiplied by
the probability of getting a 3, 4, 5 or 6 the 4th time, or {{{2/3}}}
multiplied by
the probability of getting a 3, 4, 5 or 6 the 5th time, or {{{2/3}}}
multiplied by
the probability of getting a 3, 4, 5 or 6 the 6th time, or {{{2/3}}}

So it's {{{(2/3)^8}}} or about .088

Edwin</pre>