Question 266249
let the side of original square be x meters

so area will be x^2 sq.mt

now given If the side of a square is decreased by 3 meters, the area is decreased by 45 square meters

so when the side is x-3 the area is (x-3)^2 that is given equal to x^2-45

so (x-3)^2 = x^2-45

=>   x^2-6x+9 = x^2-45

=>6x=54

so x=9

so the side of the original square is 9 meters in length