Question 266188
the perimeter of a rectangle is 24 ft. Its length is five times its width. Let x be the length and y be the width. What is the area of the rectangle?


Since x = length and y = width, and since perimeter = 24, then 2L + 2W = P becomes 2x + 2y = 24


Also, since length or x is 5 times width or y, then we'll have: x = 5y


We can then substitute 5y for x in the 1st equation to get: 2(5y) + 2y = 24 ---- > 10y + 2y = 24


12y = 24


{{{y = 24/12 = 2}}}


Since y or width = 2, then x or length = 5(2) = 10


Since width = 2 and length = 10, then area = L*W or 10 * 2 = {{{highlight_green(20)}}} feet squared.