Question 266111
Here is our system
(i){{{5x + 3y = 12}}} 
(ii) {{{4x -5y = 17}}}
step 1 - multiply (i) by 5 and (ii) by 3 to get
(iii) {{{25x + 15y = 60}}}
(iv) {{{12x - 15y = 51}}}
step 2 - add down to get
(v) {{{37x = 111}}}
divide to get
x = 3
So, y = -1