Question 265859
first I want to say your the first student Ive come accross to put your question in corrct source format. So thank you.

{{{4/(2x-6)-12/(4x+12)=12/(x^2-9)}}}
{{{4/(2(x-3))-12/(4(x+3))=12/((x-3)(x+3))}}}
{{{((2/(cross(x-3)))(cross(x-3))(x+3))-(3/(cross(x+3)))(x-3)(cross(x+3))=(12/(cross((x-3)(x+3))))(cross(x-3)cross(x+3))}}}
{{{2(x+3)-3(x-3)=12}}}
{{{2x+6-3x+9=12}}}
{{{15-x=12}}}
{{{15-12=x}}}
{{{3=x}}}

x=(3,-3)