Question 265852
A rectangle is 2 times as long as it is wide. If the area is 50 square feet, find its perimeter.
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first off Perimeter(P)= 2 Length(L) + 2 Width(W)
P=2L+2W
and Area(A)=Langth(L) times Width(W)
A=LW
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so A=50 and L=2W
.
A=LW
{{{50=2W(W)
{{{50/2=2/2(W^2)}}}
{{{sqrt(25)=sqrt(W^2)}}}
{{{5=W}}}
L=2W
{{{L=2(5)}}}
{{{L=10}}}
P=2L+2W
{{{P=2(10)+2(5)}}}
{{{P=(20+10)}}}
{{{P=30}}}