Question 265840
{{{(x^2-3)/(x-2)}}}
<pre>
The numerator has a missing power of {{{x}}},

so we must write it {{{x^2+0x-3}}}

     <u>       x + 2</u>
x - 2)x² + 0x - 3
      <u>x² - 2x</u>
           2x - 3
           <u>2x - 4</u>
                1

Answer: {{{x + 2 + 1/(x-2)}}} 

Edwin</pre>