Question 265418
f the value of 1/t-1 is twice the value of 1/t+2 , what is the value of t ?
:
{{{1/((t-1))}}} = 2({{{1/((t+2))}}})
Which is
{{{1/((t-1))}}} = {{{2/((t+2))}}}
Cross multiply
1(t+2) = 2(t-1)
t + 2 = 2t - 2
2 + 2 = 2t - t
4 = t
;
:
Check solution in original equation
{{{1/((4-1))}}} = 2({{{1/((4+2))}}})
{{{1/3}}} = {{{2/6}}}