Question 265777
{{{11x=6x^2+3}}}
<pre><font size = 4 color="indigo"><b>
Add -11x to both sides to get zero on the left

{{{0=6x^2-11x+3}}}

{{{6x^2-11x+3=0}}}

factor

{{{(2x-3)(3x-1)=0}}}

set first factor = 0

{{{2x-3=0}}}

{{{2x=3}}}

{{{x=3/2}}}, that's one solution

Set the other factor = 0

{{{3x-1=0}}}

{{{3x=1}}}

{{{x=1/3}}}, that's the other solution

Edwin</pre>