Question 265648
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The smallest three-digit number with a high-order digit of 9 is 900, but this number is less than 900 therefore it cannot have three digits.  It either has 2 digits or 1 digit.  But it can't have 1 digit because it is more than a multiple of ten.  Therefore the number has exactly two digits, and the first digit is 9.  Since the digits sum to 12, the other digit must be 3.  93.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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