Question 265706
Let x, x+2, x+4 be the three integers
from above, we get
{{{(x+2)(x+4) = 63}}}
by foiling, we get
{{{x^2 + 6x + 8 = 63}}}
subtracting, we get
{{{x^2 + 6x - 55 = 0}}}
factoring, we get
{{{(x+11)(x-5) = 0}}}
solving, we get
x = -11 and x = 5
since we want positive, we get
 5, 7, 9