Question 265700
Here is the original problem. 
{{{81b^6-3d^6}}}
we can rewrite this as
{{{3^4b^6-3d^6}}}
we see a GCF of 3, so taking that out, we get
{{{3(3^3b^6 - d^6)}}}
in the parentheses we can rewrite as
{{{3((3b^2)^3 - (d^2)^3)}}}
this is a difference of cubes and we get
{{{3((3b^2-d^2)*(9b^4 + 3(bd)^2 + d^4))}}}