Question 265636
Because 1,-2, and 10 are x-intercepts or zeros of the polynomial then (x-1), (x+2), and (x-10) are factors of the polynomial.  
So we know that
y = a(x-1)(x+2)(x-10) is our polynomial and all we have to do is find a and the point (2,-32) gives us an x and y to put in the function to determine a.
-32 = a (2-1)(2+2)(2-10)
-32 = a (1)(4)(-8)
-32 = -32a
therefore a = 1
So the polynomial y = 1(x-1)(x+2)(x-10) will pass through (2,-32)