Question 265294
How do simplify that equation
:

{{{(15y^2-30y-45)/(5y^2+10y-15)}}}
Note that you can factor out 15 in the numerator and 5 in the denominator
{{{(15(y^2-2y-3))/(5(y^2+2y-3))}}}
5 cancels into 15
{{{(3(y^2-2y-3))/((y^2+2y-3))}}}
Factor some more, but that won't help us; you can leave it like it is above.
{{{(3(y-3)(y+1))/((y+3)(y-1))}}}