Question 265448
The given equations are,
            36x-15y+50z=-10      ...(1)
            2x+25y=40            ...(2)      
            54x-5y+30z=-160      ...(3)
(1)*3=>     108x-45y+150z = -30  ...(4)
(2)*5=>     270x-25y+150z = -800 ...(5)
(4)-(5)=>   -162x-20y = 770      ...(6)
(6)*5=>     -810x-100y = 3850    ...(7)
(2)*4=>     8x+100y = 160        ...(8)
(7)+(8)=>   -802x = 4010
            x = 4010/(-802)
            x = -5
(2)=>       2*(-5)+25y = 40
            -10+25y = 40
            25y = 40+10
            y = 50/25
            y = 2
(1)=>       36*(-5)-15*2+50z = -10
            -180-30+50z = -10
            50z = 180+30-10
            50z = 200
            z = 200/50
            z = 4
So the solution is, x= -5, y= 2 and z= 4