Question 265441
let the two digit number be xy  (x- tens digit & y- units digit)

so number value=10x+y

reversed digit is yx and its value is 10y+x

given 3x = 2+4y --------------1    (so x>y and also xy>yx)

and also given that 

 (10x+y)-(10y+x) = 2(x+y)-2

=> 9x-9y = 2x+2y-2
=> 7x = 11y-2 ----------------2

multiply equation-1 by 7 and equation-2 by 3 and then subtract

we get 14+28y = 33y-6

=>   5y=20
=>   y=4

and 3x=2+16=18

so x=6

so the two digit number is 64