Question 265244
This is a mixture problem. Here is a table based on the given information:
meals . . . . . . . . % . . . . . . . . . pound . . . . . . . . . . %pounds
soybean. . . . . . .16. . . . . . . . . 320-x. . . . . . . . . . . 5120 - 16x
corn. . . . . . . . . .8. . . . . . . . . . x. . . . . . . . . . . . . . . 8x
mixture. . . . . . .15. . . . . . . . . .320 . . . . . . . . . . . . . 4800
looking at the third column, we get
5120 - 16x + 8x = 4800
combine like terms to get
 5120 - 8x = 4800
subtract 5120 to get
 -8x = -320
divide to get
x = 40
So we need 40 pounds of cornmeal and 280 pounds of soybean