<PRE><B>Question 265148</B>
Let the cost of the third adhesive = $ x 
Then, the cost of the second adhesive = $ 3x 
the cost of the first adhesive = $ 2*3x = $ 6x
Total cost x+3x+6x = 45
           10x = 45
           x = 45/10
           x = 4.5
So the most expensive adhesive = 6x = 6*4.5 = $ 27
  
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