Question 265170
The given equation is
           8x^3+4x^2-18x-9 = 0
           8x^2(2x+1)-9(2x+1) = 0
           (2x+1)(8x^2-9) = 0
           2x+1 = 0  or 8x^2-9 = 0
           2x=-1  or 8x^2 = 9
           x = -1/2  or x^2 = 9/8
           x = -1/2  or x = 3/2sqrt2  or x = -3/2sqrt2
So the solution is 
           x = -1/2 , 3/2sqrt2 and -3/2sqrt2