Question 265123
this one if you can recognize the factors off the bat it will save you from havving to do the quadratic formula. since B=0 in {{{Ax^2+Bx+C=0}}} your looking for 2 of the opposite numbers when multiplied together you get -25. so {{{(z(-z))=-25}}}
{{{-z^2=-25)}}} 
{{{z^2=25}}}
{{{sqrt(z^2)=sqrt(25))}}}
{{{z=5)}}}

with every quadratic equation theres 2 answers, from above you know "z" is both negative and positive, so 
{{{(m+(z))(m+(-z))}}} 
{{{(m+5)(m-5)}}}
m=-5,5

If you dont understand how to do this short version above then just go on to the quadratic equation solver:
{{{Ax^2+Bx+C=0}}}
{{{m^2-25=0}}} A=1 B=0 C=-25
*[invoke quadratic "m", 1, 0, -25]