Question 265062
{{{f(x)=x^2-4}}} Start with the first function 



{{{f(g(x))=(sqrt(x+1))^2-4}}} Plug in {{{g(x)=sqrt(x+1)}}}



{{{f(g(1/2))=(sqrt(1/2+1))^2-4}}} Plug in {{{x=1/2}}}



{{{f(g(1/2))=(sqrt(3/2))^2-4}}} Add the fractions.



{{{f(g(1/2))=3/2-4}}} Take the square root of {{{sqrt(3/2)}}} to get {{{3/2}}}



{{{f(g(1/2))=-5/2}}} Subtract.



So the solution is {{{f(g(1/2))=-5/2}}}