Question 264870
I think 2.


If the end points of the diameter are A and B, then the points equidistant from them would be the end points of a diameter perpendicular to the original diameter.


If the end points of this diameter were C and D, then C is equidistant from A and B, and D is equidistant from A and B.


All points, A,B,C,D, lie on the circumference of the circle.


The diameters of this circle would look like this:


<pre>


                                     C
                                     
                                     x

                                     x

                      A  x  x  x  x  x  x  x  x  x  B

                                     x

                                     x

                                     D
</pre>