Question 264818
Two planes depart from the same place at 2pm. One plane flies south at a speed of 376km/hr, and the other flies west at a speed of 648km/hr. How far apart are the airplanes at 5:30PM?

distance traveled by first plane to south in 3.5 hours= 376*3.5=1316
distance traveled by first plane to west in 3.5 hours= 648*3.5=2268

they are traveling at right angles

so apply pythagoras theorem

for finding the hypotenuse = distance

(1316)^2 +(2268)^2 = 1731856 + 5225796 = (6875680)^2 = 2622.15