<PRE><B>Question 264213</B>
 A choir is singing in a festival.
 On the first night 12 people were absent so they stood in 5 equal rows.
 On the second night only 1 was absent so they stood in 6 equal rows.
 The same number of people stood in each row each night.
 How many people are in the choir?
:
Let x = no. of people in the choir
Let r = no. of people in each row (same both nights)
:
x - 1 = 6r; 2nd night
x -12 = 5r; 1st night
-------------------------subtraction eliminates x, find r
0 + 11 = r
11 people in each row both nights
:
Find x
x - 12 = 5(11)
x = 55 + 12
x = 67 people in the choir
;
Check solution in the 2nd night equation
67 - 1 = 6*11
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