Question 264746
{{{sqrt(5w+6)-w=2}}} Start with the given equation.



{{{sqrt(5w+6)=w+2}}} Add 'w' to both sides.



{{{5w+6=(w+2)^2}}} Square both sides to eliminate the square root.



{{{5w+6=w^2+4w+4}}} FOIL



{{{0=w^2+4w+4-5w-6}}} Get all terms to one side.



{{{0=w^2-w-2}}} Combine like terms.



{{{w^2-w-2=0}}} Rearrange the equation.



{{{(w-2)(w+1)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:


{{{w-2=0}}} or  {{{w+1=0}}} 



{{{w=2}}} or  {{{w=-1}}}    Now solve for w in each case



So the <i>possible</i> answers are  {{{w=2}}} or  {{{w=-1}}} 



However, you need to check if they are actually the answers (by plugging them back into the original equation). I'll leave that up to you.