Question 264754


{{{(3x-3)^2=81}}} Start with the given equation.



{{{3x-3=""+-sqrt(81)}}} Take the square root of both sides.



{{{3x-3=sqrt(81)}}} or {{{3x-3=-sqrt(81)}}} Break up the "plus/minus" to form two equations.



{{{3x-3=9}}} or {{{3x-3=-9}}}  Take the square root of {{{81}}} to get {{{9}}}.



{{{3x=3+9}}} or {{{3x=3-9}}} Add {{{3}}} to both sides.



{{{3x=12}}} or {{{3x=-6}}} Combine like terms.



{{{x=4}}} or {{{x=-2}}} Divide both sides by {{{3}}} to isolate {{{x}}}.



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Answer:



So the solutions are {{{x=4}}} or {{{x=-2}}}.