Question 264736
{{{x + y = 4}}} Start with the second equation.



{{{x + 2x+1 = 4}}} Plug in {{{y = 2x + 1}}}



{{{3x+1=4}}} Combine like terms on the left side.



{{{3x=4-1}}} Subtract {{{1}}} from both sides.



{{{3x=3}}} Combine like terms on the right side.



{{{x=(3)/(3)}}} Divide both sides by {{{3}}} to isolate {{{x}}}.



{{{x=1}}} Reduce.



{{{y = 2x + 1}}} Move back to the first equation.



{{{y = 2(1) + 1}}} Plug in {{{x=1}}}



{{{y = 2 + 1}}} Multiply



{{{y = 3}}} Add



So the solutions are {{{x=1}}} and {{{y = 3}}} which form the ordered pair (1,3)



This means that the system is consistent and independent.