Question 264536
{{{(t^2-9)/(t+3)^2}}} Start with the given expression.



{{{((t+3)(t-3))/(t+3)^2}}} Factor the numerator.



{{{((t+3)(t-3))/((t+3)(t+3))}}} Factor the denominator.



{{{(highlight((t+3))(t-3))/(highlight((t+3))(t+3))}}} Highlight the common terms.



{{{(cross((t+3))(t-3))/(cross((t+3))(t+3))}}} Cancel out the common terms.



{{{(t-3)/(t+3)}}} Simplify.



So {{{(t^2-9)/(t+3)^2}}} simplifies to {{{(t-3)/(t+3)}}}



In other words, {{{(t^2-9)/(t+3)^2=(t-3)/(t+3)}}} where {{{t<>-3}}}