Question 264535
the line y=2x-8 meets the coordinate axes at A and B. the line AB is a diameter of the circle. find the equation of the line.
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The line crosses the x-axis at y= 0, --> (4,0).
The line crosses the y-axis at x-0, --> (0,-8)
Those are the 2 points.
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The midpoint is the center of the circle.
To find the midpoint, get the average of x and y separately.
x: (0+4)/2 = 2
y: (0-8)/2 = -4
--> M (2,-4)
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The distance from M to A or B is the radius.
{{{r^2 = diffy^2 + diffx^2}}}
{{{r^2 = 2^2 + 4^2 = 20}}}
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--> {{{(x-2)^2 + (y+4)^2 = 20}}}