Question 264483
First rearrange the equation by solving for y:
{{{3x-2y+5 = 0}}} Add 2y to both sides.
{{{3x+5 = 2y}}} Now divide through by 2 to get y by itself.
{{{(3/2)x+5/2 = y}}} or {{{y = (3/2)x+5/2}}}
Now you can graph this by first letting x = 0 and solving for y, then letting y = 0 and solving for x so that you will get two ordered pairs (points) which you can then plot on you coordinate graph paper.  Join these two points with a straight line and you will have the graph of the given equation:
{{{y = (3/2)x+5/2}}} substitute x = 0.
{{{y = (3/2)(0)+5/2}}}
{{{y = 5/2}}} The first point is ({{{0}}}, {{{5/2}}})
{{{y = (3/2)x+5/2}}} Substitute y = 0.
{{{0 = (3/2x)+5/2}}} Subtract {{{5/2}}} from both sides.
{{{-5/2 = (3/2)x}}} Multiply both sides by {{{2/3}}}.
{{{-5/3 = x}}} The second point is ({{{-5/3}}},{{{0}}})
The graph looks like this:
{{{graph(400,400,-5,5,-5,5,(3/2)x+5/2)}}}

For displaying the graph on your calculator, assuming that you have a graphing calculator such as TI-83, TI-86, etc press the "graph" key then, for {{{y[1]}}} enter {{{highlight((3/2)x+5/2)}}} followed by the "enter" or "=" key.